PROGRAM TO STORE A STRING OF 5 CHARACTERS (DYNAMIC ALLOCATION)

#include<stdio.h>

#include<malloc.h>

main()

{

char *cp;

int i;

cp=(char *)calloc(5,1);

printf("the storage address of memory\n");

printf("Block address :%u\n",cp);

printf("enter the string having 5 characters\n");

for(i=1;i<=5;i++)

{

*cp++=getchar();

printf("the character %d is %c\n",i,*(cp-1));

printf("it is stored in the address  %u\n",(cp-1));

}

}

"dynamic.c" 18L, 354C                                         10,1          All

OUTPUT:

"dynamic.c" 18L, 354C written

[staff@linuxserver staff]$ cc dynamic.c

[staff@linuxserver staff]$ ./a.out

the storage address of memory

Block address :134518568

enter the string having 5 characters

nisha

the character 1 is n

it is stored in the address  134518568

the character 2 is i

it is stored in the address  134518569

the character 3 is s

it is stored in the address  134518570

the character 4 is h

it is stored in the address  134518571

the character 5 is a

it is stored in the address  134518572