Leap year

Algorithm
Step 1 : Start
Step 2 : Read the value of year
Step 3 : If year divisible by 400 then
Print "Leap year"
Step 3.1 : else if year divisible by 4 and not divisible by 100 then
Print "Leap year"
Step 3.2 : else
Print "Not a leap year"
Step 4 : Stop

Program (leap.sh)
# Leap year
echo -n "Enter a year : "
read year
rem1=`expr $year % 4`
rem2=`expr $year % 100`
rem3=`expr $year % 400`
if [ $rem3 -eq 0 ]
then
echo "$year is a Leap Year"
elif [ $rem2 -ne 0 -a $rem1 -eq 0 ]

PROGRAM TO DETERMINE WHETHER THE GIVEN YEAR IS LEAP YEAR

echo enter a year

read n

if test `expr $n % 4` -eq 0

then

echo leap year

else

echo not a leap year

fi

~

~

OUTPUT

[staff@linuxserver staff]$ sh leap

enter a year

2008

leap year

[staff@linuxserver staff]$ sh leap

enter a year

2009

not a leap year

 PROGRAM TO GENERATE THE FINOCCI SERIES

echo "enter the number"

read n

echo "The result is"

c=0

a=0

b=1

echo "$a"

echo "$b"

n=`expr $n - 2`

while test $n -ne 0

do

c=`expr $a + $b`

echo "$c"

a=$b

b=$c

n=`expr $n - 1`

done

~

OUTPUT:

[eceb33@linuxserver eceb33]$ sh fiboo

enter the number

8

The result is

0

1

1

2

3

5

8

13